F(-2)=x^2-4x+10

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Solution for F(-2)=x^2-4x+10 equation: 



(-2)=F^2-4F+10

We move all terms to the left:

(-2)-(F^2-4F+10)=0

We add all the numbers together, and all the variables

-(F^2-4F+10)-2=0

We get rid of parentheses

-F^2+4F-10-2=0

We add all the numbers together, and all the variables

-1F^2+4F-12=0

a = -1; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·(-1)·(-12)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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